python如何获取apk的packagename和activity

这篇文章主要介绍了python如何获取apk的packagename和activity,文中通过示例代码介绍的非常详细，对大家的学习或者工作具有一定的参考学习价值,需要的朋友可以参考下

实现代码如下：

# 找出packagename和activity
import os
import re
class packagename_activity:
  def get_packagename(self, path):
    aapt = []
    os.system(f'aapt dump badging {path}> ../xc_logs/AaptLog.txt')
    with open('../xc_logs/AaptLog.txt', 'rb') as f:
      p1 = "package: name='(.+?)'"
      results1 = re.finditer(pattern=p1, string=f.readline().decode('utf-8'))
      for r in results1:
        packagename = r.group(1)
        aapt.append(packagename)
      p2 = "launchable-activity: name='(.+?)'"
      st = str(f.readlines())
      results2 = re.findall(p2, st)
      activity = results2[0]
      aapt.append(activity)
    return aapt
if __name__ == '__main__':
  a=packagename_activity()
  b=a.get_packagename('../xc_apk/wangyiyunyinyue.apk')
  print(b)

以上就是本文的全部内容，希望对大家的学习有所帮助，也希望大家多多支持python博客。