基于Python计算圆周率pi代码实例

一 计算公式：

二 实现代码

（1）

import math
from tqdm import tqdm
import time
total,s,n,t=0.0,1,1.0,1.0
while(math.fabs(t)>=1e-6):
  total+=t
  n+=2
  s=-s
  t=s/n
k=total*4
print("π值是{:.10f} 运行时间为{:.4f}秒".format(k,time.clock()))
for i in tqdm(range(101)):
  print("\r{:3}%".format(i),end="")
  time.sleep(0.1)

（2）

import time
import math


class Index(object):
  def __init__(self, number=50, decimal=2):
    self.decimal = decimal
    self.number = number
    self.a = 100/number 

  def __call__(self, now, total):
    percentage = self.percentage_number(now, total)
    well_num = int(percentage / self.a)
    progress_bar_num = self.progress_bar(well_num)
    result = "\r%s %s" % (progress_bar_num, percentage)
    return result

  def percentage_number(self, now, total):
    return round(now / total * 100, self.decimal)

  def progress_bar(self, num):
    well_num = "#" * num
    space_num = " " * (self.number - num)
    return '[%s%s]' % (well_num, space_num)
index = Index()
total,s,n,t=0.0,1,1.0,1.0
while(math.fabs(t)>=1e-6):
  total+=t
  n+=2
  s=-s
  t=s/n
k=total*4
start = 371
for i in range(start + 1):
  print(index(i, start), end='')
  time.sleep(0.01)
print("\n π值是{:.10f}".format(k))

(3)

import time
import math
total,s,n,t=0.0,1,1.0,1.0
while(math.fabs(t)>=1e-6):
  total+=t
  n+=2
  s=-s
  t=s/n
k=total*4
scale=50
print("".center(scale//2,"-"))
start = time.perf_counter()
for i in range(scale+1):
  a="*"*i
  b="."*(scale-i)
  c=(i/scale)*100
  d=time.perf_counter() - start
  print("\r{:^3.0f}%[{}->{}]{:.2f}s".format(c,a,b,d),end='')
  time.sleep(0.1)
print("\n π值是{:.10f}".format(k))

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