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python实现一个点绕另一个点旋转后的坐标

看: 798次  时间:2021-01-25  分类 : python教程

如下所示:

(x,y)为要转的点,(pointx,pointy)为中心点,如果顺时针角度为angle

srx = (x-pointx)*cos(angle) + (y-pointy)*sin(angle)+pointx

sry = (y-pointy)*cos(angle) - (x-pointx)*sin(angle)+pointy

(x,y)为要转的点,(pointx,pointy)为中心点,如果逆时针角度为angle

nrx = (x-pointx)*cos(angle) - (y-pointy)*sin(angle)+pointx

nry = (x-pointx)*sin(angle) + (y-pointy)*cos(angle)+pointy

import numpy as np
import math
import matplotlib.pyplot as plt
# 绕pointx,pointy逆时针旋转
def Nrotate(angle,valuex,valuey,pointx,pointy):
 valuex = np.array(valuex)
 valuey = np.array(valuey)
 nRotatex = (valuex-pointx)*math.cos(angle) - (valuey-pointy)*math.sin(angle) + pointx
 nRotatey = (valuex-pointx)*math.sin(angle) + (valuey-pointy)*math.cos(angle) + pointy
 return nRotatex, nRotatey
# 绕pointx,pointy顺时针旋转
def Srotate(angle,valuex,valuey,pointx,pointy):
 valuex = np.array(valuex)
 valuey = np.array(valuey)
 sRotatex = (valuex-pointx)*math.cos(angle) + (valuey-pointy)*math.sin(angle) + pointx
 sRotatey = (valuey-pointy)*math.cos(angle) - (valuex-pointx)*math.sin(angle) + pointy
 return sRotatex,sRotatey
pointx = 1
pointy = 1
sPointx ,sPointy = Nrotate(math.radians(45),pointx,pointy,0,0)
print(sPointx,sPointy)
plt.plot([0,pointx],[0,pointy])
plt.plot([0,sPointx],[0,sPointy])
plt.xlim(-3.,3.)
plt.ylim(-3.,3.)
plt.xticks(np.arange(-3.,3.,1))
plt.yticks(np.arange(-3.,3.,1))
plt.show()```

<p><img alt="" src="https://img.94e.cn/media/uploads/full/20210125/20191204090127.jpg"></p>

```python  
import numpy as np
import math
import matplotlib.pyplot as plt
# 绕pointx,pointy逆时针旋转
def Nrotate(angle,valuex,valuey,pointx,pointy):
 valuex = np.array(valuex)
 valuey = np.array(valuey)
 nRotatex = (valuex-pointx)*math.cos(angle) - (valuey-pointy)*math.sin(angle) + pointx
 nRotatey = (valuex-pointx)*math.sin(angle) + (valuey-pointy)*math.cos(angle) + pointy
 return nRotatex, nRotatey
# 绕pointx,pointy顺时针旋转
def Srotate(angle,valuex,valuey,pointx,pointy):
 valuex = np.array(valuex)
 valuey = np.array(valuey)
 sRotatex = (valuex-pointx)*math.cos(angle) + (valuey-pointy)*math.sin(angle) + pointx
 sRotatey = (valuey-pointy)*math.cos(angle) - (valuex-pointx)*math.sin(angle) + pointy
 return sRotatex,sRotatey

x1 = np.array([1,2,3])
y1 = np.array([1,2,3])
x2 = np.array([3,6])
y2 = np.array([2,1])
# x2往x1上拼
disx = x2[0]-x1[0]
disy = y2[0]-y1[0]
removeX2 = x2-disx
removeY2 = y2-disy
tany1 = y1[-1]-y1[0]
tanx1 = x1[-1]-x1[0]
angle1 = math.degrees(np.arctan(tany1/tanx1))
tany2 = y2[-1]-y2[0]
tanx2 = x2[-1]-x2[0]
angle2 = math.degrees(np.arctan(tany2/tanx2))
disAngle = angle2-angle1
print(angle1)
print(angle2)
print(disAngle)
if disAngle<0:
 rotateX,rotateY = Nrotate(math.radians(abs(disAngle)),removeX2,removeY2,x1[0],y1[0])
else:
 rotateX,rotateY = Srotate(math.radians(abs(disAngle)),removeX2,removeY2,x1[0],y1[0])
plt.plot(x1,y1,color='red')
plt.plot(removeX2,removeY2,color='green')
plt.scatter(rotateX,rotateY,color='yellow')
plt.xlim(0.,10.)
plt.ylim(0.,10.)
plt.xticks(np.arange(0.,10.,1))
plt.yticks(np.arange(0.,10.,1))
plt.show()

以上这篇python实现一个点绕另一个点旋转后的坐标就是小编分享给大家的全部内容了,希望能给大家一个参考,也希望大家多多支持python博客。

标签:numpy  matplotlib  

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