每个人产生对应的抽签码;
开始进行抽签;
公布中签结果;
这次案例写的比较简单,实际生产环境远比这复杂的多,但是万变不离其宗,基本逻辑还是差不多的……
import random
def get_random_code(num_code):
"""
生成并返回随机验证码
:param num_code: 随机验证码位数
"""
list_code = []
for i in range(num_code):
# (1)随机生成三种字符
# (1-1)随机生成0~9的数字
num = str(random.randint(0, 9))
# (1-2)随机生成小写字母
lower_alphabet = chr(random.randint(97, 122))
# (1-3)随机生成大写字母
upper_alphabet = chr(random.randint(65, 90))
# (2)再次随机抽取一个字符
random_code = random.choice([num, lower_alphabet, upper_alphabet])
# (3)保存随机抽取的字符
list_code.append(random_code)
return "".join(list_code)
def main():
# 抽签总人数
draw_num = 30
# 中签的总人数
draw_result_num = 10
# 总抽签码列表
draw_list = []
# 中签的抽签码列表
draw_result_list = []
# (1)模拟生成抽签码,实际应该是每个人自己获取抽签码,现在用循环来模拟
for i in range(draw_num):
draw_code = get_random_code(6)
while draw_code in draw_list:
# 重复标签,需要重新生成抽签码
draw_code = get_random_code(6)
else:
# 将生成的标签码加入列表
draw_list.append(draw_code)
# (2)模拟产生抽签的过程
print("总共产生了{}个抽签码:{}".format(draw_num, draw_list))
for i in range(draw_result_num):
# NO1:这种方式会总共生成的抽签码给删除,所以还是采用其它方式
# random_index = random.randint(0, len(draw_list)-1)
# draw_result_list.append(draw_list.pop(random_index))
# NO2:
a = 0
b = len(draw_list) - 1
draw_code = draw_list[random.randint(a, b)]
while draw_code in draw_result_list:
# 重复标签,重新抽签
draw_code = draw_list[random.randint(a, b)]
else:
# 将抽中的抽签码加入列表
draw_result_list.append(draw_code)
# (3)公布抽签结果
print("{}位中签的抽签码如下:".format(draw_result_num))
for item in draw_result_list:
print(item)
if __name__ == '__main__':
main()
控制台输出结果:
总共产生了30个抽签码:[‘511uCZ', ‘nAYBf8', ‘6I92sq', ‘206FxX', ‘1WMHCb', ‘sdJUMU', ‘e4A85p', ‘14Ae35', ‘n4xA44', ‘94i4eG', ‘L8981K', ‘11wtyN', ‘i5k5Xk', ‘7S8Tf7', ‘cGC4Ku', ‘f8dM40', ‘nBi958', ‘ELDVqz', ‘MQZFJQ', ‘hPPqh5', ‘Qr682E', ‘E2Z4X4', ‘IlmRJJ', ‘J71Pc1', ‘JPZpv8', ‘svAlm3', ‘9GaS9U', ‘v8378K', ‘116u2b', ‘x688xP']
10位中签的抽签码如下:
i5k5Xk
v8378K
e4A85p
J71Pc1
hPPqh5
1WMHCb
JPZpv8
sdJUMU
9GaS9UMQZFJQ
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